Electrostatics

Chapter 6 Electrostatics







6.4 Force between two electrical charges in a vacuum


Consider two charges, q1 and q2, separated by a distance, d, in a vacuum, as shown in Figure 6.1.



If we assume that both charges are of the same sign, then q1 will exert a force of repulsion (F) on q2 and q2 will exert the same force of repulsion on q1. As we have already stated above, it can be shown that:



image



Thus, F is proportional to the magnitude of each charge and to the inverse square of the distance separating them.


If we combine the factors in 1, 2 and 3 above, we can produce the equation:



Equation 6.1 image



If q1 and q2 both have the same sign, then F will be positive and will represent a force of repulsion. If the charges have opposite signs, then F will be negative and will represent a force of attraction.


If we wish to replace the proportionality sign in Equation 6.1 by an equals sign then we need to introduce a constant of proportionality (see Appendix A). This equation now reads:



Equation 6.2 image



This equation is often referred to as Coulomb’s law of force between two charges and has particular relevance when we consider the charges between subatomic particles (see Chs 18 and 19).


The constant of proportionality is image, where ε0 is the permittivity of a vacuum and has a value of 6.85 × 10−12 F.m−1. The charges q1, and q2 are expressed in coulombs, the separation d is in meters and the force F is in newtons.


The coulomb corresponds to the charge carried by 6 × 1018 electrons or protons. An alternative (and more practical) definition of the coulomb is:



Mar 6, 2016 | Posted by in GENERAL RADIOLOGY | Comments Off on Electrostatics

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